Question:

A thin rod having a length of \(1 m\) and area of cross-section \(3 \times 10^{-6} m ^2\) is suspended vertically from one end. The rod is cooled from \(210^{\circ} C\) to \(160^{\circ} C\) After cooling, a mass \(M\) is attached at the lower end of the rod such that the length of rod again becomes \(1m\). Young's modulus and coefficient of linear expansion of the rod are \(2 \times 10^{11} N m ^{-2}\) and \(2 \times 10^{-5} K ^{-1}\), respectively. The value of \(M\) is ____ \(kg\). (Take \(g =10 \ m s ^{-2}\))

Updated On: Sep 24, 2024
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Correct Answer: 60

Solution and Explanation

If Δℓ is decease in length of rod due to decease in temperature
\(Δℓ = ℓαΔT\)
\(α = 2×10^{−5} K^{−1}\)
\(ΔT = (210−160) = 50K\)
\(Δℓ =1×2×10^{−5}×50 = 10^{−3} m\)
Young Modulus \(Y = \frac {\frac FA}{\frac {​Δℓ}{ℓ}}\)        \((A = 3×10^{−6} m^2)\)

\(2×10^{11}=\frac {\frac {mg}{3 \times 10^{-6}}}{\frac {10^{-3}}{1}}\)
\(Mg = 2×10^{11}×3×10^{−9}\)
\(Mg =6×10^{2}\)
\(M \times 10 = 600\)
\(M=60 \ kg\)

So, The correct answer is 60.

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