Step 1: For a plano-convex lens, the approximate thickness of the lens \( t \) can be calculated using the formula: \[ t = \frac{R}{n - 1} \] where \( R \) is the radius of curvature, and \( n \) is the refractive index. Here, \( R = \frac{D}{2} = \frac{8.4}{2} = 4.2 \, \text{cm} \), and \( n = \frac{5}{3} \). Now, substituting the values: \[ t = \frac{4.2}{\frac{5}{3} - 1} = \frac{4.2}{\frac{2}{3}} = 4.2 \times \frac{3}{2} = 1.823 \, \text{cm} \] The thickness of the lens is approximately \( \boxed{1.8 \, \text{cm}} \).
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?
Match the following: