Step 1: For a plano-convex lens, the approximate thickness of the lens \( t \) can be calculated using the formula: \[ t = \frac{R}{n - 1} \] where \( R \) is the radius of curvature, and \( n \) is the refractive index. Here, \( R = \frac{D}{2} = \frac{8.4}{2} = 4.2 \, \text{cm} \), and \( n = \frac{5}{3} \). Now, substituting the values: \[ t = \frac{4.2}{\frac{5}{3} - 1} = \frac{4.2}{\frac{2}{3}} = 4.2 \times \frac{3}{2} = 1.823 \, \text{cm} \] The thickness of the lens is approximately \( \boxed{1.8 \, \text{cm}} \).
A hemispherical vessel is completely filled with a liquid of refractive index \( \mu \). A small coin is kept at the lowest point \( O \) of the vessel as shown in the figure. The minimum value of the refractive index of the liquid so that a person can see the coin from point \( E \) (at the level of the vessel) is:
In a messenger RNA molecule, untranslated regions (UTRs) are present at:
I. 5' end before start codon
II. 3' end after stop codon
III. 3' end before stop codon
IV. 5' end after start codon