In a telescope, the magnifying power \( M \) is given by the ratio of the focal lengths of the objective and the eyepiece:
\[
M = \frac{f_o}{f_e}.
\]
Here, \( f_o = 100 \, \text{cm} \) and \( f_e = 5 \, \text{cm} \), so the magnifying power is:
\[
M = \frac{100}{5} = 20.
\]
Thus, the magnifying power of the telescope is 20.