Step 1: Understanding the expectation value of energy.
The expectation value of energy is given by:
\[
\langle E \rangle = \langle \Psi | \hat{H} | \Psi \rangle
\]
Since the Hamiltonian \( \hat{H} \) is diagonal in the energy eigenstate basis, the energy expectation value can be computed as:
\[
\langle E \rangle = N^2 \left( E_1 + E_2 + E_3 - E_4 - E_5 \right)
\]
where \( E_n \) is the energy associated with the state \( \psi_n \), given by \( E_n = \left(n + \frac{1}{2}\right) \).
Step 2: Calculating the individual energies.
Using the given formula for \( E_n \), we compute:
\[
E_1 = \left(1 + \frac{1}{2}\right) = 1.5, \quad E_2 = \left(2 + \frac{1}{2}\right) = 2.5, \quad E_3 = \left(3 + \frac{1}{2}\right) = 3.5
\]
\[
E_4 = \left(4 + \frac{1}{2}\right) = 4.5, \quad E_5 = \left(5 + \frac{1}{2}\right) = 5.5
\]
Step 3: Substituting into the expectation value formula.
Now, substitute the energies into the expectation value equation:
\[
\langle E \rangle = N^2 \left( 1.5 + 2.5 + 3.5 - 4.5 - 5.5 \right)
\]
\[
\langle E \rangle = N^2 \times (3.5)
\]
Since the normalization constant \( N^2 \) ensures the state is normalized, we have \( N^2 = 1 \).
Step 4: Conclusion.
Thus, the expectation value of energy is \( 3.5 \).
Final Answer:
\[
\boxed{3.5}
\]