Question:

A system consists of a uniformly charged sphere of radius $R$ and a surrounding medium filled by a charge with the volume density $\rho=\frac{\alpha}{r}$, where $\alpha$ is a positive constant and $r$ is the distance from the centre of the sphere. Find the charge of the sphere for which the electric field intensity $E$ outside the sphere is independent of $R$.

Updated On: Jun 23, 2024
  • $\frac{\alpha}{2\varepsilon_{0}}$
  • $\frac{\alpha}{\alpha\varepsilon_{0}}$
  • $2\pi\alpha R^{2}$
  • None of these
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The Correct Option is C

Approach Solution - 1

Using Gauss theorem for spherical surface of radius $r$ outside the sphere with a uniform charge density $\rho$ and a charge $q$ $\int\limits_{{s}}$$E.ds=\frac{Q_{enc}}{\varepsilon_{0}}$ $E4\pi r^{2}=\frac{1}{\varepsilon_{0}}\left(q+\int\limits^r_{{R}}\frac{\alpha}{r}\left(4\pi r^{2}\right)dr\right)$; $E4\pi r^{2}=\frac{\left(q-2\pi\alpha R^{2}\right)}{\varepsilon_{0}}+\frac{4\pi\alpha r^{2}}{2\varepsilon_{0}}$ The intensity $E$ does not depend on $R$ if $\frac{q-2\pi\alpha R^{3}}{\varepsilon_{0}}=0$ or $q=2\pi\alpha R^{2}$
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Approach Solution -2

Given:
A uniformly charged sphere of radius R with charge Q.
Surrounding medium with charge volume density \(\rho = \frac{\alpha}{r}\), where \(\alpha\) is a positive constant and r is the distance from the center of the sphere.

Electric Field Due to Sphere:
The electric field \(E_{\text{sphere}}\) outside a uniformly charged sphere of radius R and charge Q is:
\(E_{\text{sphere}} = \frac{Q}{4 \pi \epsilon_0 r^2}\)

Electric Field Due to Surrounding Medium:
The electric field \(E_{\text{medium}}\) due to the surrounding charge density \(\rho = \frac{\alpha}{r}\) for r \(\gt\) R is:
\(E_{\text{medium}} = \frac{\alpha}{2 \epsilon_0}\)

Total Electric Field Outside the Sphere:
The total electric field \(E_{\text{total}}\) outside the sphere is the sum of \(E_{\text{sphere}}\) and \(E_{\text{medium}}\):
\(E_{\text{total}} = E_{\text{sphere}} + E_{\text{medium}}\)
\(E_{\text{total}} = \frac{Q}{4 \pi \epsilon_0 r^2} + \frac{\alpha}{2 \epsilon_0}\)

Condition for E to be Independent of R:
For \(E_{\text{total}}\) to be independent of R, the term \(\frac{Q}{4 \pi \epsilon_0 r^2}\) must equal \(\frac{\alpha}{2 \epsilon_0}\):
\(\frac{Q}{4 \pi \epsilon_0 r^2} = \frac{\alpha}{2 \epsilon_0}\)
\(Q = 2 \pi \alpha R^2\)

So, the correct option is (C): \(2 \pi \alpha R^2\)

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Concepts Used:

Electric charges and field

What is Electric Charge

It is the property of subatomic particles that experiences a force when put in an electric and magnetic field.

What is Electric Field

It is a property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by E, called electric field strength or electric field intensity.

Electric charges are of two types: Positive and Negative. It is commonly carried by charge carriers protons and electrons.

Properties of Electric Charge

Various properties of charge include the following :-

Types of electric charge

Two kinds of electric charges are there :-

Negative Charge - When an object has a negative charge it means that it has more electrons than protons.

Positive Charge - When an object has a positive charge it means that it has more protons than electrons.

When there is an identical number of positive and negative charges, the negative and positive charges would cancel out each other and the object would become neutral.