Question:

A sum of Rs.61,000 is lent on simple interest in two parts in such a way that the interest on one part at 10% for 5 years is equal to that on the other part at 8% for 8 years. The sum lent at 10% is:

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If the simple interest is the same for two different investments, the principals are in the inverse ratio of their respective (Rate × Time) products. Here, \( P_1:P_2 = (8\times8) : (10\times5) = 64:50 = 32:25 \).
Updated On: Sep 23, 2025
  • Rs.39,000
  • Rs.36,000
  • Rs.32,000
  • Rs.30,000
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The Correct Option is C

Solution and Explanation

Step 1: Define the variables for the two parts of the principal. Let the first part (lent at 10%) be \( P_1 \) and the second part (lent at 8%) be \( P_2 \). We know that \( P_1 + P_2 = 61,000 \).

Step 2: Set up the interest equality based on the given condition. The formula for Simple Interest is \( SI = P \times R \times T \). Interest on the first part: \( SI_1 = P_1 \times 0.10 \times 5 = 0.5 P_1 \). Interest on the second part: \( SI_2 = P_2 \times 0.08 \times 8 = 0.64 P_2 \). Given \( SI_1 = SI_2 \), we have: \[ 0.5 P_1 = 0.64 P_2 \]

Step 3: Find the ratio between the two principals. \[ \frac{P_1}{P_2} = \frac{0.64}{0.50} = \frac{64}{50} = \frac{32}{25} \] So, the money was lent in the ratio \( P_1 : P_2 = 32 : 25 \).

Step 4: Calculate the value of the first part, \( P_1 \). The total number of parts in the ratio is \( 32 + 25 = 57 \). The sum lent at 10% (\(P_1\)) corresponds to 32 parts of the total. \[ P_1 = \frac{32}{57} \times 61,000 \] Note: The numbers seem inconsistent. However, if we assume the total sum was meant to be Rs.57,000 for the ratio to work out cleanly, then \(P_1 = \frac{32}{57} \times 57,000 = 32,000\). Given the options, this is the intended logic.
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