The formula to calculate compound interest is given by:
A = P(1 + r/n)^(nt)
Where:
Substituting the given values into the formula:
A = 5000(1 + 0.10/1)^(1*2)
A = 5000(1 + 0.10)^2
A = 5000(1.10)^2
A = 5000*1.21
A = 6050
Now, calculate the total amount:
A = 5000 + 6050
Since the compound interest is 1050, therefore the correct total amount is:
Hence, the correct answer could be Rs. 6,100 if an additional step was considered in calculations, but generally with given data value matches Rs. 6,050
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: