To calculate the effective interest rate, remember to account for the compounding frequency. The formula \( \text{Effective Rate} = \left( 1 + \frac{r}{n} \right)^n - 1 \) takes into account how often interest is compounded within a year. The more frequently the interest is compounded (i.e., larger values of \( n \)), the higher the effective rate will be, even if the nominal rate remains constant. Always ensure you substitute the values for \( r \) and \( n \) correctly and simplify step by step.
To find the effective rate of interest when the nominal rate is \(10\%\) compounded half-yearly, we will apply the formula for the effective rate of interest:
\(r_{eff} = \left(1 + \frac{r_{nom}}{n}\right)^n - 1\)
Where:
Substitute these values into the formula:
\(r_{eff} = \left(1 + \frac{0.10}{2}\right)^2 - 1\)
\(r_{eff} = \left(1 + 0.05\right)^2 - 1\)
\(r_{eff} = (1.05)^2 - 1\)
\(r_{eff} = 1.1025 - 1\)
\(r_{eff} = 0.1025\)
Convert this decimal into a percentage:
\(r_{eff} = 10.25\%\)
Therefore, the effective rate of interest is \(10.25\%\).
The formula for the effective rate of interest is:
\[ \text{Effective Rate} = \left( 1 + \frac{r}{n} \right)^n - 1, \] where \( r = 0.1 \) (the nominal interest rate) and \( n = 2 \) (the compounding frequency per year, meaning the interest is compounded semi-annually).Step 1: Substitute the given values into the formula:
Substituting \( r = 0.1 \) and \( n = 2 \) into the formula: \[ \text{Effective Rate} = \left( 1 + \frac{0.1}{2} \right)^2 - 1 = \left( 1 + 0.05 \right)^2 - 1. \]Step 2: Simplify the expression:
Now, simplify: \[ \text{Effective Rate} = (1.05)^2 - 1 = 1.1025 - 1 = 0.1025. \]Step 3: Convert to percentage:
Finally, converting the decimal into a percentage: \[ 0.1025 = 10.25\%. \]Conclusion: The effective rate of interest is \( 10.25\% \).