This question is based on conceptual clarity that we should connect ammeter in series and voltmeter in parallel to measure current and potential difference, respectively. Also, when using a galvanometer to create an ammeter, shunt resistance should be very small and should be in parallel.
When we create a voltmeter shunt should be large and in series with the galvanometer.
All these criteria are satisfied in option (2).
An alternating voltage is given by \( e = 8 \sin(628.4 t) \).
Find:
(i) Peak value of e.m.f.
(ii) Frequency of e.m.f.
(iii) Instantaneous value of e.m.f. at time \( t = 10 \, {ms} \)