Question

A straight wire of length $0.5\,\text{m$ and carrying current of $1.2\,\text{A}$ is placed in a uniform magnetic field of induction $2\,\text{T}$. The magnetic field is perpendicular to the length of the wire. What is the force acting on the wire? $\left[\sin 90^\circ = 1\right]$}

• A. $2.0\,\text{N}$
• B. $2.4\,\text{N}$
• C. $1.2\,\text{N}$
• D. $3.0\,\text{N}$

Hint:

Maximum magnetic force occurs when the conductor is perpendicular to the magnetic field.

Answer 1

The Correct Option is C

Step 1: Formula for magnetic force on a current-carrying conductor.
\[ F = B I L \sin\theta \]

Step 2: Substitute given values.
\[ F = 2 \times 1.2 \times 0.5 \times 1 \]

Step 3: Calculate force.
\[ F = 1.2 \,\text{N} \]

Step 4: Conclusion.
The force acting on the wire is $1.2\,\text{N}$.