Question

A straight conductor $0.1\, m$ long moves in a uniform magnetic field $0.1\, T$. The velocity of the conductor is $15\, m / s$ and is directed perpendicular to the field. The emf induced between the two ends of the conductor is

• A. 0.10 V
• B. 0.15 V
• C. 1.50 V
• D. 15.00 V

Answer 1

The Correct Option is B

Given, length of conductor $l=0.1\, m$
Mangetic field, $B=0.1\, T$
Velocity of conductor, $v=15\, m / s$
The angle between $v$ and $B$ is $90^{\circ}$
When $v$ and $B$ are mutually perpendicular, then emf (induced) is given by
$\varepsilon=v B l=15 \times 0.1 \times 0.1$
$=\frac{15}{100}=0.15\, V$