Step 1: The tension in the string depends on both the centripetal force and the gravitational force acting on the stone. At the highest position, the stone is moving upwards, and gravity opposes the tension in the string.
Step 2: The tension in the string is given by the equation: \[ T = \frac{mv^2}{r} - mg. \] At the highest position, the tension is the smallest because the gravitational force acts in the same direction as the centripetal force.
Step 3: Hence, the tension in the string is minimum at the highest point of the circular path.
Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
Current passing through a wire as function of time is given as $I(t)=0.02 \mathrm{t}+0.01 \mathrm{~A}$. The charge that will flow through the wire from $t=1 \mathrm{~s}$ to $\mathrm{t}=2 \mathrm{~s}$ is:
In the figure shown below, a resistance of 150.4 $ \Omega $ is connected in series to an ammeter A of resistance 240 $ \Omega $. A shunt resistance of 10 $ \Omega $ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA.