Step 1: Use the transformer formula.
For a transformer, the voltage and current are related by the following formula:
\[
\frac{V_1}{V_2} = \frac{N_1}{N_2}, \quad \frac{I_1}{I_2} = \frac{N_2}{N_1}
\]
where \( V_1 \) and \( V_2 \) are the voltages, \( I_1 \) and \( I_2 \) are the currents, and \( N_1 \) and \( N_2 \) are the number of turns in the primary and secondary windings, respectively.
Step 2: Apply the formula.
Given that \( N_1 = 300 \), \( N_2 = 450 \), \( V_1 = 150 \, \text{V} \), and \( I_1 = 9 \, \text{A} \), we can find \( V_2 \) and \( I_2 \):
\[
V_2 = \frac{N_2}{N_1} \times V_1 = \frac{450}{300} \times 150 = 225 \, \text{V}
\]
\[
I_2 = \frac{N_1}{N_2} \times I_1 = \frac{300}{450} \times 9 = 6.0 \, \text{A}
\]
Step 3: Conclusion.
The current and voltage in the secondary are \( 6.0 \, \text{A} \) and \( 225 \, \text{V} \), so the correct answer is (D).