Question

A steel plate is fastened to a channel using three identical bolts as shown in the figure. The bolts are made of carbon steel of permissible yield strength in shear as 400 N/mm². The plate is subjected to a force of 12 kN. Neglect the weight of the plate. The magnitude of the resultant shear force (in N) on bolt 2 is ............. (Answer in integer) 

Hint:

In problems involving uniform force distribution across identical fasteners, simply divide the total force by the number of fasteners to calculate the force on each.

Answer 1

In this problem, the plate is subjected to a force of 12 kN, and this force is distributed across three identical bolts. Since the bolts are identical and assume the force distribution is uniform, each bolt will experience an equal amount of force. To calculate the force on each bolt, we divide the total force by the number of bolts: \[ F_{{each bolt}} = \frac{12 \, {kN}}{3} = 4 \, {kN} \] Since 1 kN = 1000 N, we convert this to newtons: \[ F_{{each bolt}} = 4 \, {kN} = 4000 \, {N} \] Thus, the resultant shear force acting on each bolt, including bolt 2, is \( 4000 \, {N} \).