The correct answer is option (B): 82000 g/mol
Explanation: The osmotic pressure formula is given by:
\(\pi = \frac{nRT}{V}\)
Where:
Substitute into the formula:
\[ 3.0 \times 10^{-4} = \frac{\left(\frac{4}{M}\right)(0.08206)(300)}{4} \]
Multiply both sides by 4:
\[ 1.2 \times 10^{-3} = \frac{(4)(0.08206)(300)}{M} \]
Solve for M:
\[ M = \frac{(4)(0.08206)(300)}{1.2 \times 10^{-3}} = \frac{98.472}{1.2 \times 10^{-3}} = 82060 \approx 82000 \text{ g/mol} \]
Hence, the molar mass of the polymer is approximately 82000 g/mol.
According to the generally accepted definition of the ideal solution there are equal interaction forces acting between molecules belonging to the same or different species. (This is equivalent to the statement that the activity of the components equals the concentration.) Strictly speaking, this concept is valid in ecological systems (isotopic mixtures of an element, hydrocarbons mixtures, etc.). It is still usual to talk about ideal solutions as limiting cases in reality since very dilute solutions behave ideally with respect to the solvent. This law is further supported by the fact that Raoult’s law empirically found for describing the behaviour of the solvent in dilute solutions can be deduced thermodynamically via the assumption of ideal behaviour of the solvent.
Answer the following questions:
(a) Give one example of miscible liquid pair which shows negative deviation from Raoult’s law. What is the reason for such deviation?
(b) (i) State Raoult’s law for a solution containing volatile components.
OR
(ii) Raoult’s law is a special case of Henry’s law. Comment.
(c) Write two characteristics of an ideal solution.
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of:
Solutions are homogeneous mixtures of two or more substances, where the solute is uniformly dispersed in the solvent. Solutions can be classified into several types based on their composition and properties.
Understanding the different types of solutions is important for understanding their properties, behavior, and applications in various fields, such as chemistry, biology, and engineering.