Question:

A solid uniform sphere resting on a rough horizontal plane is given a horizontal impulse directed through its center so that it starts sliding with an initial velocity $v_0$. When it finally starts rolling without slipping the speed of its center is

Updated On: Apr 19, 2024
  • $\frac{2}{7}v_{0}$
  • $\frac{3}{7}v_{0}$
  • $\frac{5}{7}v_{0}$
  • $\frac{6}{7}v_{0}$
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The Correct Option is C

Solution and Explanation

Let, the final velocity be $v$


So, angular momentum will remain conserved along point of contact
By conservation of angular momentum
Angular momentum will remain conserved along point of contact
$I \omega=$ constant
$ m v_{0} r =m v r+\frac{2}{5} m r^{2} \times \omega\,\,\, \left(\because \omega=\frac{v}{r}\right) $
$ m v_{0} r =m v r+\frac{2}{5} m r^{2}\left(\frac{v}{r}\right) $
$v_{0} =v+\frac{2}{5} v $
$ v_{0} =\frac{7}{5} v $
$\Rightarrow v=\frac{5}{7} v_{0} $
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System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.