A small telescope has an objective lens of focal length 144cm and an eyepiece of focal length 6.0cm. What is the magnifying power of the telescope?What is the separation between the objective and the eyepiece?
A small telescope has an objective lens of focal length 144cm and an eyepiece of focal length 6.0cm. What is the magnifying power of the telescope?What is the separation between the objective and the eyepiece?
Solution and Explanation
The focal length of the objective lens,fo=144cm
Focal length of the eyepiece,fe=6.0cm
The magnifying power of the telescope is given as m=\(\frac{f_o}{f_e}\)=\(\frac{144}{6}\)=24
The separation between the objective lens and the eyepiece is calculated as:ƒº+ƒe=144+6=150cm
Hence, the magnifying power of the telescope is 24 and the separation between the objective lens and the eyepiece is 150cm.
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Concepts Used:
Ray Optics and Optical Instruments
Optics, deals with the determination of behaviour and the properties of light, along with its interactions with the matter and also with the instruments that are used to detect it.
Ray optics is also known as the geometrical optics and it is a branch of science which describes light propagation.
Reflection is the change in direction of light at an interface in-between two different media so that the wave-front returns into a medium from which it was originated.
Speed of light is the rate at which the light travels in free space.
A phenomenal change in image formed when the light is passed from one medium to another which is called Refraction.
Total Internal Reflection is the reflection of light when the light ray enters into a rarer medium from a denser medium and the angle of incidence is higher than the critical angle of incidence then that light ray will be reflected back to the denser medium.
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