Question:

A small circular loop of area AA and resistance RR is fixed on a horizontal xyx y-plane with the center of the loop always on the axis n^\hat{n} of a long solenoid The solenoid has mm turns per unit length and carries current II counterclockwise as shown in the figure The magnetic field due to the solenoid is in n^\hat{ n } direction List-I gives time dependences of n^\hat{ n } in terms of a constant angular frequency ω\omega List-II gives the torques experienced by the circular loop at time t=π6ωt=\frac{\pi}{6 \omega}, Let α=A2μ02m2I2ω2R\alpha=\frac{A^2 \mu_0^2 m^2 I^2 \omega}{2 R} 
A small circular loop of area

Column I

Column II

I

12(sinωtj^+cosωtk^)\frac{1}{\sqrt{2}}(\sin \omega t \hat{j}+\cos \omega t \hat{k})

P

0

II

12(sinωti^+cosωtj^)\frac{1}{\sqrt{2}}(\sin \omega t \hat{i}+\cos \omega t \hat{j})

Q

α4i^-\frac{\alpha}{4} \hat{i}

III

12(sinωti^+cosωtk^)\frac{1}{\sqrt{2}}(\sin \omega t \hat{i}+\cos \omega t \hat{k})

R

3α4i^\frac{3 \alpha}{4} \hat{i}

IV

12(cosωti^+sinωtk^)\frac{1}{\sqrt{2}}(\cos \omega t \hat{i}+\sin \omega t \hat{k})

S

α4j^\frac{\alpha}{4} \hat{j}

 

 

T

3α4i^-\frac{3 \alpha}{4} \hat{i}
















Which one of the following options is correct?

Updated On: May 28, 2024
  • IQ,IIP,IIIS,IVTI \rightarrow Q , II \rightarrow P , III \rightarrow S , IV \rightarrow T
  • IS,IIT,IIIQ,IVPI \rightarrow S , II \rightarrow T, III \rightarrow Q, IV \rightarrow P
  • IQ,IIP,IIIS,IVRI \rightarrow Q , II \rightarrow P , III \rightarrow S , IV \rightarrow R
  • IT,IIQ,IIIP,IVRI \rightarrow T , II \rightarrow Q , III \rightarrow P , IV \rightarrow R
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The Correct Option is C

Solution and Explanation

IQ,IIP,IIIS,IVRI \rightarrow Q , II \rightarrow P , III \rightarrow S , IV \rightarrow R
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter