A shell of mass $10\, kg$ is moving with a velocity of $ 10\,ms^{-1}$ when it blasts and forms two parts of mass $9 \,kg$ and $1 \,kg$ respectively. If the $1^{st}$ mass is stationary, the velocity of the $ 2^{nd} $ is
- 1 m/s
- 10 m/s
- 100 m/s
- 1000 m/s
The Correct Option is C
Solution and Explanation
$v_{2}=0 ; m_{2}=9\, kg$
$v_{3}=v ; m_{3}=1\, kg$
According to conservation of momentum
$m_{1} v_{1}=m_{2} v_{2}+m_{3} v_{3}$
$10 \times 10=9 \times 0+1 \times v$
$\Rightarrow v=100\, m / s$
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Reason (R): The amplitude and phase can be expressed in terms of \( x_0 \) and \( p_0 \).
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Concepts Used:
Momentum
It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.
the momentum of an object is the product of mass of the object and the velocity of the object.
Momentum = mass • velocity
The above equation can be rewritten as
p = m • v
where m is the mass and v is the velocity.
Momentum is a vector quantity and the direction of the of the vector is the same as the direction that an object.