8H+ + 5Fe2+ + MnO – → 5Fe3+ + Mn2+ + 4H2O
For 25 ml,
meq of Fe2+ = meq of MnO –
= 12.5 × 0.03 × 5
For 250 ml,
m moles of Fe2+ = \(12.5 \times 0.03 \times 5 \times \frac{250}{25}\)
moles of Fe2+ = \(\frac{18.75}{1000}\)mol
= 18.75 × 10–3 mol
= 1.875 × 10–2 mol
x = 1.875
Weight of Fe2+ = 1.875 × 10–2 × 56 = 1.05 g
% purity of Fe2+ y = 18.75%
The steam volatile compounds among the following are:
Choose the correct answer from the options given below:
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
\[ \begin{array}{|c|c|} \hline \textbf{LIST-I (Redox Reaction)} & \textbf{LIST-II (Type of Redox Reaction)} \\ \hline A. \, CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l) & I. \, \text{Disproportionation reaction} \\ B. \, 2NaH(s) \rightarrow 2Na(s) + H_2(g) & II. \, \text{Combination reaction} \\ C. \, V_2O_5(s) + 5Ca(s) \rightarrow 2V(s) + 5CaO(s) & III. \, \text{Decomposition reaction} \\ D. \, 2H_2O(aq) \rightarrow 2H_2(g) + O_2(g) & IV. \, \text{Displacement reaction} \\ \hline \end{array} \]
List-I | List-II | ||
P | The capacitance between S1 and S4, with S2 and S3 not connected, is | I | \(3C_0\) |
Q | The capacitance between S1 and S4, with S2 shorted to S3, is | II | \(\frac{C_0}{2}\) |
R | The capacitance between S1 and S3, with S2 shorted to S4, is | III | \(\frac{C_0}{3}\) |
S | The capacitance between S1 and S2, with S3 shorted to S1, and S2 shorted to S4, is | IV | \(2\frac{C_0}{3}\) |
\[2C_0\] |