Question:

A rifle shoots a bullet with a muzzle velocity of $ 500\,m{{s}^{-1}} $ at a small target 50 m away. To hit the target the rifle must be aimed: (Take $ g=10\,m{{s}^{-2}} $ )

Updated On: Aug 19, 2024
  • exactly at the target
  • 10 cm below the target
  • 10 cm above the target
  • 5 cm above the target
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The Correct Option is D

Solution and Explanation

We know that distance
$ \text{(sd)}\,\text{=}\,\text{speed}\,\text{(v)}\,\text{ }\!\!\times\!\!\text{ }\,\text{time}\,\text{(t)} $
$ \Rightarrow $ $ t=\frac{s}{v} $
Given, $ v=500\,m{{s}^{-1}},s=50\,m $
$ \therefore $ $ t=\frac{50}{500}=0.1\,s $
From equation of motion, for vertical displacement
$ h=ut+\frac{1}{2}g{{t}^{2}} $
Given, $ u=0,t=0.1\,s $
$ \therefore $ $ h=\frac{1}{2}\times 10\times {{(0.1)}^{2}}=0.05\,m=5\,cm. $
Hence, the rifle must be aimed 5 cm above the target.
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration