Solution: To determine the power dissipated in the resistor, we will use the formula for electrical power: \( P = \frac{V^2}{R} \), where \( P \) is the power in watts, \( V \) is the voltage across the resistor in volts, and \( R \) is the resistance in ohms.
Given:
- \( V = 12 \, \text{V} \)
- \( R = 10 \, \Omega \)
Substitute the given values into the formula:
\( P = \frac{12^2}{10} \)
\( P = \frac{144}{10} \)
\( P = 14.4 \, \text{W} \)
Therefore, the power dissipated in the resistor is 14.4 W.