A relation \( R = \{(a, b) : a = b - 2, b \geq 6 \} \) is defined on the set \( \mathbb{N} \). Then the correct answer will be:
The given relation is \( R = \{(a, b) : a = b - 2, b \geq 6\} \).
For each pair:
For \( (2, 4) \): \( a = 4 - 2 = 2 \) and \( b = 4 \).
Since \( b \geq 6 \) is not satisfied, \( (2, 4) \notin R \).
For \( (3, 8) \): \( a = 8 - 2 = 6 \) and \( b = 8 \). Since \( a \neq 3 \), \( (3, 8) \notin R \).
For \( (6, 8) \): \( a = 8 - 2 = 6 \) and \( b = 8 \).
Both conditions \( a = b - 2 \) and \( b \geq 6 \) are satisfied, so \( (6, 8) \in R \).
For \( (8, 7) \): \( a = 7 - 2 = 5 \) and \( b = 7 \).
Since \( a \neq 8 \), \( (8, 7) \notin R \).
Thus, the correct pair is \( (6, 8) \).
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
Let $ A $ be the set of all functions $ f: \mathbb{Z} \to \mathbb{Z} $ and $ R $ be a relation on $ A $ such that $$ R = \{ (f, g) : f(0) = g(1) \text{ and } f(1) = g(0) \} $$ Then $ R $ is:
If the domain of the function $ f(x) = \log_7(1 - \log_4(x^2 - 9x + 18)) $ is $ (\alpha, \beta) \cup (\gamma, \delta) $, then $ \alpha + \beta + \gamma + \delta $ is equal to
Let $ A = \{-2, -1, 0, 1, 2, 3\} $. Let $ R $ be a relation on $ A $ defined by $ (x, y) \in R $ if and only if $ |x| \le |y| $. Let $ m $ be the number of reflexive elements in $ R $ and $ n $ be the minimum number of elements required to be added in $ R $ to make it reflexive and symmetric relations, respectively. Then $ l + m + n $ is equal to
Find the values of \( x, y, z \) if the matrix \( A \) satisfies the equation \( A^T A = I \), where
\[ A = \begin{bmatrix} 0 & 2y & z \\ x & y & -z \\ x & -y & z \end{bmatrix} \]
(b) Order of the differential equation: $ 5x^3 \frac{d^3y}{dx^3} - 3\left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^4 + y = 0 $