A relation \( R = \{(a, b) : a = b - 2, b \geq 6 \} \) is defined on the set \( \mathbb{N} \). Then the correct answer will be:
The given relation is \( R = \{(a, b) : a = b - 2, b \geq 6\} \).
For each pair:
For \( (2, 4) \): \( a = 4 - 2 = 2 \) and \( b = 4 \).
Since \( b \geq 6 \) is not satisfied, \( (2, 4) \notin R \).
For \( (3, 8) \): \( a = 8 - 2 = 6 \) and \( b = 8 \). Since \( a \neq 3 \), \( (3, 8) \notin R \).
For \( (6, 8) \): \( a = 8 - 2 = 6 \) and \( b = 8 \).
Both conditions \( a = b - 2 \) and \( b \geq 6 \) are satisfied, so \( (6, 8) \in R \).
For \( (8, 7) \): \( a = 7 - 2 = 5 \) and \( b = 7 \).
Since \( a \neq 8 \), \( (8, 7) \notin R \).
Thus, the correct pair is \( (6, 8) \).
Let $R$ be a relation defined on the set $\{1,2,3,4\times\{1,2,3,4\}$ by \[ R=\{((a,b),(c,d)) : 2a+3b=3c+4d\} \] Then the number of elements in $R$ is
Let \(M = \{1, 2, 3, ....., 16\}\), if a relation R defined on set M such that R = \((x, y) : 4y = 5x – 3, x, y (\in) M\). How many elements should be added to R to make it symmetric.