Let the width of the path be 'x' meters.
Length of the outer rectangle (including the path) = (55 + 2x) meters
Breadth of the outer rectangle (including the path) = (25 + 2x) meters
Area of the outer rectangle = (55 + 2x)(25 + 2x) square meters
Area of the inner rectangle (plot) = \(55 \times 25 = 1375 \) square meters
Given, Area of the path = Area of the plot
Therefore, (55 + 2x)(25 + 2x) - 1375 = 1375
Expanding and simplifying the equation, we get:
\(4x^2 + 160x - 1375 = 0\)
Solving this quadratic equation for x, we get x = \(5\sqrt{2} - 5\)
