Question

A reaction of phenol with chloroform in presence of sodium hydroxide to form salicylaldehyde is known as

• A. Reimer - Tiemann reaction
• B. Friedel craft’s reaction
• C. Stephens reaction
• D. Kolbe’s reaction

Hint:

The Reimer-Tiemann reaction is a key method for introducing an aldehyde group into the ortho position of phenol using chloroform and NaOH.

Answer 1

The Correct Option is A

Step 1: Understanding the Reimer-Tiemann reaction.
The Reimer-Tiemann reaction involves the reaction of phenol with chloroform (CHCl\(_3\)) in the presence of sodium hydroxide (NaOH) to form salicylaldehyde (o-hydroxybenzaldehyde). This reaction is used to introduce an aldehyde group (-CHO) into the ortho position of a phenol ring.
Step 2: Analyzing the options.
(A) Reimer - Tiemann reaction: This is the correct answer. The reaction between phenol, chloroform, and NaOH is known as the Reimer-Tiemann reaction.
(B) Friedel craft’s reaction: This involves alkylation or acylation of an aromatic compound using a Lewis acid catalyst, not the same as the Reimer-Tiemann reaction.
(C) Stephens reaction: This is incorrect. The Stephens reaction involves the reduction of nitriles, not phenols.
(D) Kolbe’s reaction: This involves the decarboxylation of phenol, not its reaction with chloroform.
Step 3: Conclusion.
The correct answer is (A) Reimer - Tiemann reaction.