The correct option is(B): 4:1
\(KE=\frac{p^2}{2m}=\frac{h^2}{2mλ^2} \)
\(\frac{KE_p}{KE_α}=\frac{m_α}{m_p}=4:1\)
De-Broglie wavelength is given by: \[ \lambda = \frac{h}{p} \] Equating for both particles: \[ \frac{KE_p}{KE_\alpha} = \frac{m_\alpha}{m_p} = 4:1 \]
Einstein's Explanation of the Photoelectric Effect:
Einstein explained the photoelectric effect on the basis of Planck’s quantum theory, where light travels in the form of small bundles of energy called photons.
The energy of each photon is hν, where:
The number of photons in a beam of light determines the intensity of the incident light.When a photon strikes a metal surface, it transfers its total energy hν to a free electron in the metal.A part of this energy is used to eject the electron from the metal, and this required energy is called the work function.The remaining energy is carried by the ejected electron as its kinetic energy.
The dual nature of matter and the dual nature of radiation were throughgoing concepts of physics. At the beginning of the 20th century, scientists untangled one of the best-kept secrets of nature – the wave-particle duplexity or the dual nature of matter and radiation.
Electronic Emission
The least energy that is needed to emit an electron from the surface of a metal can be supplied to the loose electrons.
Photoelectric Effect
The photoelectric effect is a phenomenon that involves electrons getting away from the surface of materials.
Heisenberg’s Uncertainty Principle states that both the momentum and position of a particle cannot be determined simultaneously.