Given:
Electric field in x and y: equal amplitude, in phase.
Propagation along z-axis.
Linear Polarization at 45°:
Equal amplitudes and same phase ⇒ resultant vector lies along 45$^\circ$.
$E_x = E_0 cos(\omega t)$ and $E_y = E_0 cos(\omega t)$.
So, net E-field = $\vec{E} = E_0 (\hat{i} + \hat{j}) cos(\omega t)$ ⇒ angle = 45$^\circ$ to x-axis.