Question:

A plane EM wave of frequency $25~\text{MHz}$ propagates in vacuum. If electric field is $6.3~\text{V/m}$, then magnitude of magnetic field is

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In EM waves, $B = \dfrac{E}{c}$ with $c = 3 \times 10^8~\text{m/s}$.
Updated On: Jun 4, 2025
  • $2.1 \times 10^{-8}~\text{T}$
  • $4.2 \times 10^{-8}~\text{T}$
  • $6.3 \times 10^{-8}~\text{T}$
  • $8.4 \times 10^{-8}~\text{T}$
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The Correct Option is A

Solution and Explanation

$B = \dfrac{E}{c} = \dfrac{6.3}{3 \times 10^8} = 2.1 \times 10^{-8}~\text{T}$
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