The amount of heat added to the cylinder at constant pressure can be calculated using the equation:
\[
Q = m \cdot c_p \cdot \Delta T
\]
where:
- \( Q \) is the heat added (in kJ),
- \( m \) is the mass of the gas (in kg),
- \( c_p \) is the specific heat at constant pressure (in kJ/kg-K),
- \( \Delta T \) is the change in temperature (in K).
Step 1: For the hydrogen (H\(_2\)) gas, the mass is \( m_H = 4 \, {kg} \), the specific heat is \( c_p(H_2) = 14.239 \, {kJ/kg-K} \), and the temperature change is:
\[
\Delta T_H = 350 \, {K} - 250 \, {K} = 100 \, {K}
\]
Thus, the heat added to hydrogen is:
\[
Q_H = m_H \cdot c_p(H_2) \cdot \Delta T_H = 4 \cdot 14.239 \cdot 100 = 5695.6 \, {kJ}
\]
Step 2: For the nitrogen (N\(_2\)) gas, the mass is \( m_N = 13 \, {kg} \), the specific heat is \( c_p(N_2) = 1.040 \, {kJ/kg-K} \), and the temperature change is:
\[
\Delta T_N = 350 \, {K} - 250 \, {K} = 100 \, {K}
\]
Thus, the heat added to nitrogen is:
\[
Q_N = m_N \cdot c_p(N_2) \cdot \Delta T_N = 13 \cdot 1.040 \cdot 100 = 1352 \, {kJ}
\]
Step 3: The total heat added to the mixture is the sum of the heat added to hydrogen and nitrogen:
\[
Q_{{total}} = Q_H + Q_N = 5695.6 \, {kJ} + 1352 \, {kJ} = 7047.6 \, {kJ}
\]
Step 4: Converting the heat from kJ to MJ:
\[
Q_{{total}} = \frac{7047.6}{1000} = 7.048 \, {MJ}
\]
Step 5: Therefore, the amount of heat added to the cylinder is approximately \( 7.048 \, {MJ} \), which lies between 6.9 and 7.2, and is closest to 7.048 MJ. So, the correct answer is within the specified range.