Let the amount of work done by Ram in one day be \( R \), and by Mohan in one day be \( M \).
We are told that Ram can complete the work in 10 days, so \( R = \frac{1}{10} \) (since work is done in one day).
When Mohan joins, both complete the work in 6 days, so:
\[
R + M = \frac{1}{6}.
\]
Substituting \( R = \frac{1}{10} \) into the equation:
\[
\frac{1}{10} + M = \frac{1}{6} \quad \Rightarrow \quad M = \frac{1}{6} - \frac{1}{10} = \frac{5 - 3}{30} = \frac{2}{30} = \frac{1}{15}.
\]
Thus, Mohan does \( M = \frac{1}{15} \) of the work in one day.
Now, the ratio of their one day work is:
\[
\frac{R}{M} = \frac{\frac{1}{10}}{\frac{1}{15}} = \frac{15}{10} = 3:2.
\]
Thus, the ratio of their one day work is 3:2, which corresponds to option (3).