\(\tan = \frac{perpendicular}{base}\)
So, in right angled triangle,
\(\tan 45\degree = \frac{\text{height of tower}}{\text{breadth of river}}\)
Since \(\tan 45\degree = 1\)
\(\therefore\) \(\text{height of tower = breadth of river}\)
Hence, the correct option is (B): The breadth of the river and the height of the tower are the same
The shadow of a tower on level ground is $30\ \text{m}$ longer when the sun's altitude is $30^\circ$ than when it is $60^\circ$. Find the height of the tower. (Use $\sqrt{3}=1.732$.)