Question:

A person moves 30 m north, from there 20m east and finally $30\sqrt{2}$ m south-west from there His displacement from initial position is.

Updated On: Jul 7, 2022
  • 10 m west
  • 10 m east
  • 5 m west
  • 5 m east
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The Correct Option is A

Solution and Explanation

$\bar{S} = 30 \hat{j} + 20 \hat{i} + 30( - \hat{i} - \hat{j})$ $\Rightarrow \, \bar{S} = - 10 \hat{j} \, \Rightarrow 10 m \, west$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration