Question:

A person invested a certain amount of money at 10% annual interest, compounded half-yearly. After one and a half years, the interest and principal together became Rs 18522. The amount, in rupees, that the person had invested is [This Question was asked as TITA]

Updated On: Jul 24, 2025
  • 15000
  • 17000
  • 16000
  • 18000
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The Correct Option is C

Solution and Explanation

We are given:

  • Final Amount \( A = 18522 \)
  • Rate of Interest \( r = 10\% = 0.10 \)
  • Time \( t = 1.5 \) years
  • Compounded Half-Yearly → \( n = 2 \)
  • Principal \( P = ? \)

The compound interest formula for half-yearly compounding is:

\[ A = P \left(1 + \frac{r}{n} \right)^{nt} \]

Substituting values:

\[ 18522 = P \left(1 + \frac{0.10}{2} \right)^{2 \times 1.5} \] \[ 18522 = P (1.05)^3 \] \[ 18522 = P \times 1.157625 \]

Solving for \( P \):

\[ P = \frac{18522}{1.157625} \approx 16000 \]

Final Answer: The initial principal invested was: \[ \boxed{16000} \]

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