Given :
Mass of ball = m
Initial velocity = u
Final velocity = v
Now,
\(⇒e=\frac{\text{Veloctiy of seperation}}{\text{Velocity of approach}}\)
\(⇒1=\frac{v_2-v_1}{u_2-u_1}\)
\(1=\frac{v_0-v}{u+v}\)
⇒ u + v = v0 - v
⇒ v0 = u + 2v
So, the correct option is (C) : u + 2v.

Potential energy (V) versus distance (x) is given by the graph. Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low. 
Read More: Work and Energy