Given :
Mass of ball = m
Initial velocity = u
Final velocity = v
Now,
\(⇒e=\frac{\text{Veloctiy of seperation}}{\text{Velocity of approach}}\)
\(⇒1=\frac{v_2-v_1}{u_2-u_1}\)
\(1=\frac{v_0-v}{u+v}\)
⇒ u + v = v0 - v
⇒ v0 = u + 2v
So, the correct option is (C) : u + 2v.
Read More: Work and Energy