Question:

A particle is projected with velocity $u$ inclined at an angle $\alpha$ with $x-axis$. Change in velocity of the particle on return to ground is

Updated On: Jul 5, 2022
  • $zero$
  • $2 \,u$
  • $2u \,cos\, \alpha$
  • $2u \,sin\,\alpha$
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The Correct Option is D

Solution and Explanation

Initial velocity along y axis = u sin $\alpha$ Final velocity along y axis = - u sin $\alpha$ Change in velocity = u sin $\alpha$ - $(-u\,sin\,\alpha)$ = $2\,u\,sin\,\alpha$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration