Question:
A particle is projected from ground at an angle 45$^\circ$ with initial velocity $20\sqrt{2}ms^{-1}$. The magnitude of average velocity in a time interval from t = 0 to t = 3s in $ms^{-1}$ is.
A particle is projected from ground at an angle 45$^\circ$ with initial velocity $20\sqrt{2}ms^{-1}$. The magnitude of average velocity in a time interval from t = 0 to t = 3s in $ms^{-1}$ is.
Updated On: Jul 5, 2022
- 20 .62
- 10.31
- 41 .14
- 5.15
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The Correct Option is A
Solution and Explanation
u = u$_x$ i + u$_y$ j
u$_f$ = u$_x$i +(u$_y$ - gt) j, $V_{avg} = \frac{u_i+ u_ f}{2}$
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Notes on Motion in a plane
Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration