Question:

A particle is moving along a circular path of radius $5 \,m $ with a uniform speed $5\, ms^{ - 1 } $ What will be the average acceleration when the particle completes half revolution ?

Updated On: Jun 20, 2022
  • Zero
  • $10\,ms^{ - 2 } $
  • $10 \,\pi\, ms^{ - 2 } $
  • $ \frac{ 10 }{ \pi } ms^{ - 2 } $
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The Correct Option is D

Solution and Explanation

When the particle completes half revolution, change in velocity
$\triangle v=[5-(-5)] \,m s^{-1}=10\, ms ^{-1}$
Time taken to complete the half revolution is
$t =\frac{\pi r}{v}=\frac{\pi \times 5}{5}=\pi$ second
Thus, average acceleration
$a_{v}=\frac{\Delta v}{t}=\frac{10}{\pi}\, m s^{-2}$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration