Equation of pair of tangents is given by $S S_{1}=T^{2}$
or $S=x^{2}+y^{2}+20(x +y)+20, S_{1}=20$,
$T=10(x +y)+20=0$
$\therefore S S_{1}=T^{2}$
$\Rightarrow 20\left(x^{2}+y^{2}+20(x +y)+20\right)=10^{2}$
$(x+y+2) 2$
$\Rightarrow 4 x^{2}+4 y^{2}+10 x y=0$
$\Rightarrow 2 x^{2}+2 y^{2}+5 x y=0$