Question:

A number is chosen at random from the set $\{1,2,3, \ldots , 2000\} $ Let $p$ be the probability that the chosen number is a multiple of $3$ or a multiple of $7$. Then the value of $500\, p$ is_____

Updated On: May 23, 2024
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Correct Answer: 214

Solution and Explanation

E = a number which is multiple of 3 or multiple of 7

n(E) = (3, 6, 9, …….., 1998) + (7, 14, 21, ……….., 1995) – (21, 42, 63, ……… 1995)

n(E) = 666+ 285 – 95

n(E) = 856

n(E) = 2000

P(E) = \(\frac{856}{2000}\)

P(E) × 500 = \(\frac{856}{4}\) = 214

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