This is a problem of arranging 6 stripes where no two adjacent stripes can have the same colour. There are 4 colours available. For the first stripe, we have 4 choices, for the second stripe, we have 3 choices (since it can't be the same colour as the first), and for each of the remaining 4 stripes, we again have 3 choices. Thus, the total number of ways to design the flag is:
\[
4 \times 3 \times 3 \times 3 \times 3 \times 3 = 4 \times 3^5 = 20 \times 125
\]
Therefore, the Correct Answer is \( 20 \times 125 \).
\[
\boxed{20 \times 125}
\]