Question:

A mixture of hydrogen and oxygen has volume 2000 \(cm^3\), temperature 300 K, pressure 100 kPa and mass 0.76 g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be:[Take gas constant R = 8.3 \(JK^{–1}\) \(mol^{–1}\)]

Updated On: Sep 24, 2024
  • \(\frac{1}{3}\)
  • \(\frac{3}{1}\)
  • \(\frac{1}{16}\)
  • \(\frac{16}{1}\)
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The Correct Option is B

Solution and Explanation

\(P_1V = n_1RT\)

\(P_2V = n_2RT\)

\(⇒ (100 kPa) V = (n_1 + n_2)RT\)

\(⇒n_1+n_2=\frac{(100 kPa)(2000 cm)^3)}{8.3×300}….(1)\)

Also, \(n_1 × 2 + n_2 × 32 = 0.76 ….(2)\)

Solving (1) and (2),

\(n_1 = 0.06\)

\(n_2 = 0.02\)

\(⇒ \frac{n_1}{n_2} = 3\)

Hence, the correct option is (B): \(\frac{3}{1}\) 

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Questions Asked in JEE Main exam

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Concepts Used:

Gas Laws

The gas laws were developed at the end of the 18th century, when scientists began to realize that relationships between pressure, volume and temperature of a sample of gas could be obtained which would hold to approximation for all gases.

The five gas laws are:

  • Boyle’s Law, which provides a relationship between the pressure and the volume of a gas.
  • Charles’s Law, which provides a relationship between the volume occupied by a gas and the absolute temperature.
  • Gay-Lussac’s Law, which provides a relationship between the pressure exerted by a gas on the walls of its container and the absolute temperature associated with the gas.
  • Avogadro’s Law, which provides a relationship between the volume occupied by a gas and the amount of gaseous substance.
  • The Combined Gas Law (or the Ideal Gas Law), which can be obtained by combining the four laws listed above.