Solution:
To find the time required to coat the metal surface, we use Faraday's law of electrolysis: \[ m = \frac{M I t}{n F}, \] where:
\( m \) is the mass of the substance deposited,
\( M \) is the molar mass of the substance (nickel, 60 g/mol),
\( I \) is the current (2 A),
\( t \) is the time in seconds,
\( n \) is the valency of the substance (for nickel, \( n = 2 \)),
\( F \) is the Faraday constant (96500 C/mol).
We are given that the thickness of the nickel layer is 0.001 mm (0.0001 cm), so the volume of the nickel deposited is: \[ V = \text{Area} \times \text{Thickness} = 100 \, \text{cm}^2 \times 0.0001 \, \text{cm} = 0.01 \, \text{cm}^3. \] Using the density of nickel \( \rho_{\text{Ni}} = 10 \, \text{g/mL} \), we can calculate the mass of the deposited nickel: \[ m = \rho_{\text{Ni}} \times V = 10 \times 0.01 = 0.1 \, \text{g}. \] Now, substitute into Faraday’s equation: \[ 0.1 = \frac{60 \times 2 \times t}{2 \times 96500}. \] Solving for \( t \): \[ t = \frac{0.1 \times 2 \times 96500}{60 \times 2} = 160.83 \, \text{seconds}. \] Thus, the time required to coat the desired layer is approximately 161 seconds.
If \[ \frac{dy}{dx} + 2y \sec^2 x = 2 \sec^2 x + 3 \tan x \cdot \sec^2 x \] and
and \( f(0) = \frac{5}{4} \), then the value of \[ 12 \left( y \left( \frac{\pi}{4} \right) - \frac{1}{e^2} \right) \] equals to: