A metal surface is illuminated by a radiation of wavelength 4500 Å. The rejected photo-electron enters a constant magnetic field of 2 mT making an angle of 90° with the magnetic field. If it starts revolving in a circular path of radius 2 mm, the work function of the metal is approximately:
- 1.36 eV
- 1.69 eV
- 2.78 eV
- 2.23 eV
The Correct Option is A
Solution and Explanation
The correct answer is (A): 1.36 eV
Explanation:
\(\frac{hc}{λ}\) - Ø = ΚΕ........(i)
R =\(\frac{ mv}{Bq}\) = \(\sqrt{\frac{2m(KE)}{Bq }}\) ........(ii)
Putting the values,
Ø ≃ 1.36 eV
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