Question:

A metal exists as an oxide with formula M0.96OM_{0.96}O. Metal MM can exist as M2+M^{2+} and M3+M^{3+} in its oxide M0.96OM_{0.96}O. The percentage of M3+M^{3+} in the oxide is nearly

Updated On: May 15, 2024
  • 0.083
  • 0.046
  • 0.05
  • 0.096
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The Correct Option is A

Solution and Explanation

Let, the number of M2+M ^{2+} ions =x= x Then, the number of M3+M ^{3+} ions will be 0.96x0.96- x We know, the overall charge in the metal oxide is zero. So, x(2)+(0.96x)(3)+1(2)=0x(2)+(0.96-x)(3)+1(-2)=0 2x+2.883x=2\Rightarrow 2 x+2.88-3 x=2 x=0.88\Rightarrow- x =-0.88 x=0.88\Rightarrow x =0.88 \therefore Number of M3+M ^{3+} ions =0.960.88=0.08=0.96-0.88=0.08 \therefore Percentage of M3+M ^{3+} ions =0.08/0.96×100=8.33%=0.08 / 0.96 \times 100=8.33 \%
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