Question:
A man walks one km east, two km north, one km east, one km north, one km east, one km north. What is the shortest distance from the starting point to the destination?
A man walks one km east, two km north, one km east, one km north, one km east, one km north. What is the shortest distance from the starting point to the destination?
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When finding shortest distance after multiple moves in right angles, use net displacement and Pythagoras theorem.
Updated On: Aug 7, 2025
- $2\sqrt{2}$ km
- 7 km
- $3\sqrt{2}$ km
- 5 km
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The Correct Option is D
Solution and Explanation
Total movement:
East: $1 + 1 + 1 = 3$ km
North: $2 + 1 + 1 = 4$ km
Shortest distance = direct displacement
Use Pythagoras:
\[
\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = \boxed{5 \text{ km}}
\]
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