A long string is stretched by $2\, cm$ and the potential energy is $V$. If the spring is stretched by $10\, cm$, its potential energy will be
- V/25
- V/5
- 5 V
- 25 V
The Correct Option is D
Solution and Explanation
or $k =\frac{2 V}{4}=\frac{V}{2}$
$V'=\frac{1}{2} k(10)^{2}=\frac{1}{2} \times\left(\frac{V}{2}\right)(10)^{2}$
$=25\, V$
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Concepts Used:
Energy In Simple Harmonic Motion
We can note there involves a continuous interchange of potential and kinetic energy in a simple harmonic motion. The system that performs simple harmonic motion is called the harmonic oscillator.
Case 1: When the potential energy is zero, and the kinetic energy is a maximum at the equilibrium point where maximum displacement takes place.
Case 2: When the potential energy is maximum, and the kinetic energy is zero, at a maximum displacement point from the equilibrium point.
Case 3: The motion of the oscillating body has different values of potential and kinetic energy at other points.