A linearly polarized light beam travels from origin to point A (1,0,0). At the point A, the light is reflected by a mirror towards point B (1, -1,0). A second mirror located at point B then reflects the light towards point C (1,-1,1). Let n(x, y, z) represent the direction of polarization of light at (x, y, z).
If \(\hat{n}\)(0, 0, 0) = \(\hat{y}\), then \(\hat{n}\)(1, -1, 1) = \(\hat{x}\)
If \(\hat{n}\)(0, 0, 0) = \(\hat{z}\), then \(\hat{n}\)(1, -1, 1) = \(\hat{y}\)
If \(\hat{n}\)(0, 0, 0) = \(\hat{y}\), then \(\hat{n}\)(1, -1, 1) = \(\hat{y}\)
If \(\hat{n}\)(0, 0, 0) = \(\hat{z}\), then \(\hat{n}\)(1, -1, 1) = \(\hat{x}\)
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The Correct Option isA, B
Solution and Explanation
The correct option is (A): If \(\hat{n}\)(0, 0, 0) = \(\hat{y}\), then \(\hat{n}\)(1, -1, 1) = \(\hat{x}\) and (B): If \(\hat{n}\)(0, 0, 0) = \(\hat{z}\), then \(\hat{n}\)(1, -1, 1) = \(\hat{y}\)