Question:

A light wave of wavelength 600 nm passes from air into a medium with refractive index 1.5. What is the wavelength of light in the medium?

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Wavelength of light in a medium = $\lambda/n$, where $\lambda$ is original wavelength and $n$ is the refractive index.
Updated On: May 30, 2025
  • 400 nm
  • 450 nm
  • 500 nm
  • 600 nm
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The Correct Option is A

Approach Solution - 1

When light enters a medium with refractive index \( n \), its speed and wavelength decrease, but frequency remains constant. The wavelength in the medium is given by: \[ \lambda' = \frac{\lambda}{n} \] Given: \[ \lambda = 600 \, \text{nm}, \quad n = 1.5 \] \[ \lambda' = \frac{600}{1.5} = 400 \, \text{nm} \]
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Approach Solution -2

To solve the problem, we need to find the wavelength of light in a medium with refractive index 1.5 when the light of wavelength 600 nm passes from air into the medium.

1. Relation Between Wavelength and Refractive Index: 
The wavelength of light in a medium is given by:
$ \lambda_{\text{medium}} = \frac{\lambda_{\text{air}}}{n} $
where $n$ is the refractive index of the medium, $\lambda_{\text{air}}$ is the wavelength in air, and $\lambda_{\text{medium}}$ is the wavelength in the medium.

2. Given Data:
$ \lambda_{\text{air}} = 600\, \text{nm} $
$ n = 1.5 $

3. Calculating Wavelength in Medium:
$ \lambda_{\text{medium}} = \frac{600}{1.5} = 400\, \text{nm} $

Final Answer:
The wavelength of light in the medium is $ {400\, \text{nm}} $.

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