To solve the problem, we need to find the wavelength of light in a medium with refractive index 1.5 when the light of wavelength 600 nm passes from air into the medium.
1. Relation Between Wavelength and Refractive Index:
The wavelength of light in a medium is given by:
$ \lambda_{\text{medium}} = \frac{\lambda_{\text{air}}}{n} $
where $n$ is the refractive index of the medium, $\lambda_{\text{air}}$ is the wavelength in air, and $\lambda_{\text{medium}}$ is the wavelength in the medium.
2. Given Data:
$ \lambda_{\text{air}} = 600\, \text{nm} $
$ n = 1.5 $
3. Calculating Wavelength in Medium:
$ \lambda_{\text{medium}} = \frac{600}{1.5} = 400\, \text{nm} $
Final Answer:
The wavelength of light in the medium is $ {400\, \text{nm}} $.
Calculate the angle of minimum deviation of an equilateral prism. The refractive index of the prism is \(\sqrt{3}\). Calculate the angle of incidence for this case of minimum deviation also.