To solve the problem, we need to find the wavelength of light in a medium with refractive index 1.5 when the light of wavelength 600 nm passes from air into the medium.
1. Relation Between Wavelength and Refractive Index:
The wavelength of light in a medium is given by:
$ \lambda_{\text{medium}} = \frac{\lambda_{\text{air}}}{n} $
where $n$ is the refractive index of the medium, $\lambda_{\text{air}}$ is the wavelength in air, and $\lambda_{\text{medium}}$ is the wavelength in the medium.
2. Given Data:
$ \lambda_{\text{air}} = 600\, \text{nm} $
$ n = 1.5 $
3. Calculating Wavelength in Medium:
$ \lambda_{\text{medium}} = \frac{600}{1.5} = 400\, \text{nm} $
Final Answer:
The wavelength of light in the medium is $ {400\, \text{nm}} $.
For the reaction \( A + B \to C \), the rate law is found to be \( \text{rate} = k[A]^2[B] \). If the concentration of \( A \) is doubled and \( B \) is halved, by what factor does the rate change?