Step 1: Lift Calculation
The total lift \( L \) on a lifting surface is related to the circulation distribution by the Kutta-Joukowski theorem: \[ L = \rho V_\infty \int_{-b/2}^{b/2} \Gamma(y) \, dy \] However, in this problem, the circulation distribution \( \Gamma(\theta) = A \sin 3\theta \) is given with odd symmetry (because of the \( \sin 3\theta \) term), and when integrated over the span, the total circulation results in zero: \[ \int_{-b/2}^{b/2} \Gamma(y) \, dy = 0 \] Therefore, the total lift \( L \) is zero.
Step 2: Induced Drag Calculation
The induced drag \( D_i \) is related to the downwash distribution, which is given by: \[ w(\theta) = V_\infty \left( \frac{3A \sin 3\theta}{\sin \theta} \right) \] Since the downwash is nonzero, the interaction between the circulation and the downwash will produce a nonzero induced drag. The induced drag \( D_i \) is given by: \[ D_i = \int_{-b/2}^{b/2} \frac{\Gamma(y) w(\theta)}{V_\infty} \, dy \] This results in a nonzero induced drag because the downwash \( w(\theta) \) is nonzero and varies along the span. Thus, \( L = 0 \) and \( D_i \neq 0 \).
The lift per unit span for a spinning circular cylinder in a potential flow is 6 N/m. The free-stream velocity is 30 m/s, and the density of air is 1.225 kg/m\(^3\). The circulation around the cylinder is __________ m\(^2\)/s (rounded off to two decimal places).
For a three-bar truss loaded as shown in the figure, the magnitude of the force in the horizontal member AB is ____________ N (answer in integer).
A 4 × 4 digital image has pixel intensities (U) as shown in the figure. The number of pixels with \( U \leq 4 \) is:
Column-I has statements made by Shanthala; and, Column-II has responses given by Kanishk.
The number of patients per shift (X) consulting Dr. Gita in her past 100 shifts is shown in the figure. If the amount she earns is ₹1000(X - 0.2), what is the average amount (in ₹) she has earned per shift in the past 100 shifts?