Step 1: Lift Calculation
The total lift \( L \) on a lifting surface is related to the circulation distribution by the Kutta-Joukowski theorem:
\[
L = \rho V_\infty \int_{-b/2}^{b/2} \Gamma(y) \, dy
\]
However, in this problem, the circulation distribution \( \Gamma(\theta) = A \sin 3\theta \) is given with odd symmetry (because of the \( \sin 3\theta \) term), and when integrated over the span, the total circulation results in zero:
\[
\int_{-b/2}^{b/2} \Gamma(y) \, dy = 0
\]
Therefore, the total lift \( L \) is zero.
Step 2: Induced Drag Calculation
The induced drag \( D_i \) is related to the downwash distribution, which is given by:
\[
w(\theta) = V_\infty \left( \frac{3A \sin 3\theta}{\sin \theta} \right)
\]
Since the downwash is nonzero, the interaction between the circulation and the downwash will produce a nonzero induced drag. The induced drag \( D_i \) is given by:
\[
D_i = \int_{-b/2}^{b/2} \frac{\Gamma(y) w(\theta)}{V_\infty} \, dy
\]
This results in a nonzero induced drag because the downwash \( w(\theta) \) is nonzero and varies along the span.
Thus, \( L = 0 \) and \( D_i \neq 0 \).